document.write( "Question 366533: a local commuter train leaves washington at 6 am averaging 36 mph at 7:15 am, a high speed express train leaves the same station traveling on a on a paralel track at 81 mph when will the express train catch up to the local commuter
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Algebra.Com's Answer #261196 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "d = r*t
\n" ); document.write( "Let t represent the time the express train travels.
\n" ); document.write( "then (t + 1.25hr) is the time the local commuter travels (1hr and 15min = 1.25hr)
\n" ); document.write( "Distance will be the same when the express train catches up to the local commuter***
\n" ); document.write( "36mph(t + 1.25hr)= 81mph*t
\n" ); document.write( "36*1.25hr = 45mph*t
\n" ); document.write( "1 hr = t, the time the express train travels and will catch up to the local commuter\r
\n" ); document.write( "\n" ); document.write( "checking our answer
\n" ); document.write( "36mph*2.25hr = 81mph*1hr = 81mi\r
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