document.write( "Question 366485: A parabola with an equation of the form y = ax^2 + bx + c has the point (-2, 1) as its vertex. If (-4, 5) also lies on the parabola, which of the following is
\n" ); document.write( "another point on this parabola?\r
\n" ); document.write( "\n" ); document.write( "(A) (-4, 3) (B) (-1, 3) (C) (0, 5) (D) (2, 1) (E) (4, 5)
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Algebra.Com's Answer #261186 by Fombitz(32388)\"\" \"About 
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Since the vertex occurs at (\"-2\",\"1\"), the line of symmetry is \"x=-2\".
\n" ); document.write( "Since (\"-4\",\"5\") is a point on the line, find the x value equidistant from the line of symmetry.
\n" ); document.write( "The x-distance from (\"-4\",\"5\") to the line of symmetry is \"d%5Bx%5D=-2-%28-4%29=2\".
\n" ); document.write( "Then add \"d%5Bx%5D=2\" to the x position of the line of symmetry x position to get the point symmetric to (\"-4\",\"5\").
\n" ); document.write( "\"x%5B2%5D=-2%2B2=0\"
\n" ); document.write( "\"y%5B2%5D=5\"
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\n" ); document.write( "(\"0\",\"5\") is another point on the parabola.
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