document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366442>Question 366442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of variation for the given situation. \r<BR>\n" );
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document.write( "y varies inversely as the square of x, and y = 7 when x = 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261151 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+k%2Fx%5E2 ALIGN=MIDDLE  ALT=\"y+=+k%2Fx%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > from the inverse relationship, where k is the constant of proportionality.  When y = 7, x = 3, so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7+=+k%2F3%5E2+=+k%2F9 ALIGN=MIDDLE  ALT=\"7+=+k%2F3%5E2+=+k%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Hence k = 63, and therefore the variation equation is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+63%2Fx%5E2 ALIGN=MIDDLE  ALT=\"y+=+63%2Fx%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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