document.write( "Question 366455: In the xy-coordinate plane, the graph of x = y^2 - 4 intersects line L at (0,p) and (5,t). What is the greatest possible value of the slope L? \n" ); document.write( "

Algebra.Com's Answer #261128 by robertb(5830) $\"\"$ $\"About$

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First of all the graph of the relation is a parabola lying sideways opening to the right , having y-intercepts (0,2) and (0,-2), and vertex (-4,0). Since L intersects the parabola at (0,p), p is either 2 or -2. Also, since (5,t) is an intersection point, t is either 3 or -3. (Why?)Hence there are four possible lines:
\n" ); document.write( "1) One passing through (0,2) and (5,-3) with slope -1,
\n" ); document.write( "2) One passing through (0,-2) and (5,-3) with slope -1/5,
\n" ); document.write( "3)One passing through (0,2) and (5,3) with slope 1/5,
\n" ); document.write( "4)One passing through (0,-2) and (5,3) with slope 1.
\n" ); document.write( "So now you know the answer! =) \n" ); document.write( "

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