document.write( "Question 366395: A woman driving a car 14 ft long is passing a truck 30 ft long. The truck is traveling at 50 mi/h. How fast must the woman drive her car so that she can pass the truck completely in 6 s, from the position shown in figure (a) to the position shown in figure (b)? [Hint: Use feet and seconds instead of miles and hours.]
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Algebra.Com's Answer #261103 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A woman driving a car 14 ft long is passing a truck 30 ft long. The truck is traveling at 50 mi/h. How fast must the woman drive her car so that she can pass the truck completely in 6 s, from the position shown in figure (a) to the position shown in figure (b)? [Hint: Use feet and seconds instead of miles and hours.] \n" ); document.write( ".. \n" ); document.write( "length of truck = 30 ft. \n" ); document.write( "length of car = 14 ft. \n" ); document.write( ".. \n" ); document.write( "to completely pass the truck the car has to travel a distance of 30+14 = 44 feet. \n" ); document.write( ".. \n" ); document.write( "speed of truck = 50 mph \n" ); document.write( "1 mph = 1.46 ft/s \n" ); document.write( "50mph = 73.33 ft/s \n" ); document.write( ".. \n" ); document.write( "let car travel at x ft/s \n" ); document.write( ".. \n" ); document.write( "they are going in the same direction \n" ); document.write( "effective speed = x-73.33 ft/s \n" ); document.write( ".. \n" ); document.write( "distance = 44ft \n" ); document.write( "speed = x-73.33 \n" ); document.write( "time = 6 seconds \n" ); document.write( ".. \n" ); document.write( "44/(x-73.33)= 6 \n" ); document.write( "44= 6(x-73.33) \n" ); document.write( "44=6x-439.98 \n" ); document.write( "6x=439.98+44 \n" ); document.write( "6x= 483.98 \n" ); document.write( "/6 \n" ); document.write( "x= 483.98/6 \n" ); document.write( "x= 80.66 ft/s the speed of the car \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |