document.write( "Question 366395: A woman driving a car 14 ft long is passing a truck 30 ft long. The truck is traveling at 50 mi/h. How fast must the woman drive her car so that she can pass the truck completely in 6 s, from the position shown in figure (a) to the position shown in figure (b)? [Hint: Use feet and seconds instead of miles and hours.]
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Algebra.Com's Answer #261103 by mananth(16946)\"\" \"About 
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A woman driving a car 14 ft long is passing a truck 30 ft long. The truck is traveling at 50 mi/h. How fast must the woman drive her car so that she can pass the truck completely in 6 s, from the position shown in figure (a) to the position shown in figure (b)? [Hint: Use feet and seconds instead of miles and hours.]
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\n" ); document.write( "length of truck = 30 ft.
\n" ); document.write( "length of car = 14 ft.
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\n" ); document.write( "to completely pass the truck the car has to travel a distance of 30+14 = 44 feet.
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\n" ); document.write( "speed of truck = 50 mph
\n" ); document.write( "1 mph = 1.46 ft/s
\n" ); document.write( "50mph = 73.33 ft/s
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\n" ); document.write( "let car travel at x ft/s
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\n" ); document.write( "they are going in the same direction
\n" ); document.write( "effective speed = x-73.33 ft/s
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\n" ); document.write( "distance = 44ft
\n" ); document.write( "speed = x-73.33
\n" ); document.write( "time = 6 seconds
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\n" ); document.write( "44/(x-73.33)= 6
\n" ); document.write( "44= 6(x-73.33)
\n" ); document.write( "44=6x-439.98
\n" ); document.write( "6x=439.98+44
\n" ); document.write( "6x= 483.98
\n" ); document.write( "/6
\n" ); document.write( "x= 483.98/6
\n" ); document.write( "x= 80.66 ft/s the speed of the car
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\n" ); document.write( "m.ananth@hotmail.ca
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