document.write( "Question 366404: John and Jim are going on a bike ride. On the trip to mill park, they ride at an average of 8 mph on a route that is 4 miles less than the route on the return trip. They travel 7 mph on the return trip. If it takes them 1hour longer to return than to go, how much total time do they spend riding their bikes? \n" ); document.write( "
Algebra.Com's Answer #261098 by mananth(16946)\"\" \"About 
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John and Jim are going on a bike ride. On the trip to mill park, they ride at an average of 8 mph on a route that is 4 miles less than the route on the return trip. They travel 7 mph on the return trip. If it takes them 1hour longer to return than to go, how much total time do they spend riding their bikes?
\n" ); document.write( "return trip distance be x miles
\n" ); document.write( "forward distance to mill park ---- x-4 miles
\n" ); document.write( "..
\n" ); document.write( "speed to mill park = 8 mph
\n" ); document.write( "return speed = 7 mph
\n" ); document.write( "..
\n" ); document.write( " return time -time to go to mill park = 1 hour
\n" ); document.write( "..
\n" ); document.write( "t=d/r
\n" ); document.write( "..
\n" ); document.write( "x/7-(x-4)/8 =1
\n" ); document.write( "(8x-7(x-4))/56=1
\n" ); document.write( "8x-7x+28=56
\n" ); document.write( "x=56-28
\n" ); document.write( "x=28 miles return distance
\n" ); document.write( "forward distance = 28-4 = 24 miles
\n" ); document.write( "..
\n" ); document.write( "t= d/r
\n" ); document.write( "28/7 + 24/8 = 7 hours
\n" ); document.write( "so They spend 7 hours riding
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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