document.write( "Question 366301: Kesha had only pennies and dimes in her change purse. When she counted out her change, she had 54 cents. If she had 6 times as many pennies as she did dimes, how many pennies did she have?\r
\n" ); document.write( "\n" ); document.write( "I need an equation for this one and I started off with
\n" ); document.write( "p+d=54
\n" ); document.write( "d=6p
\n" ); document.write( "After this, i get stuck. I did it without an equation and got 24 pennies. \n" ); document.write( "
Algebra.Com's Answer #261049 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Kesha had only pennies and dimes in her change purse. When she counted out her change, she had 54 cents. If she had 6 times as many pennies as she did dimes, how many pennies did she have?\r
\n" ); document.write( "\n" ); document.write( "I need an equation for this one and I started off with
\n" ); document.write( "p+d=54
\n" ); document.write( "d=6p
\n" ); document.write( "After this, i get stuck. I did it without an equation and got 24 pennies.
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document.write( "That's because you have both equation wrong.  Also 54 should be 64. It comes\r\n" );
document.write( "out fractions with 54, so it must have been 64.\r\n" );
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document.write( "To get money you can't add coins to coins.  \r\n" );
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document.write( "You have p+d=54.  Not only should the 54 be 64, but\r\n" );
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document.write( "pennies + dimes = cents\r\n" );
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document.write( "is senseless, it's like\r\n" );
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document.write( "apples + oranges = bananas.\r\n" );
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document.write( "Your equation must not be \r\n" );
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document.write( "copper coins + silver coins = amount of money.\r\n" );
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document.write( "You must have\r\n" );
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document.write( "amount of money + amount of money = amount of money \r\n" );
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document.write( "cents + cents = cents.\r\n" );
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document.write( "p pennies is worth p cents,\r\n" );
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document.write( "d dimes is worth 10p cents.\r\n" );
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document.write( "So your first equation is\r\n" );
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document.write( "p + 10d = 64, not p+d=64, and certainly not p+d=54\r\n" );
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document.write( "You also interpreted this clause wrong:\r\n" );
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\n" ); document.write( ">>If she had 6 times as many pennies as she did dimes,<<
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document.write( "Notice these three examples:\r\n" );
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document.write( "If she had 2 dimes, she would have 12 pennies.\r\n" );
document.write( "If she had 3 dimes, she would have 18 pennies\r\n" );
document.write( "If she had 5 dimes, she would have 60 pennies.\r\n" );
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document.write( "So to get the number of pennies you must mutiply the number of dimes by 6.\r\n" );
document.write( "So you have it backwards.\r\n" );
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document.write( "Its p=6d, not d=6p\r\n" );
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document.write( "So the two equation should be:\r\n" );
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document.write( "p+10d=64\r\n" );
document.write( "p=6d\r\n" );
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document.write( "Substitute 6d for p in the first equation\r\n" );
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document.write( "6d+10d=64\r\n" );
document.write( "   16d=64\r\n" );
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document.write( "divide both sides by 16\r\n" );
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document.write( "     d=4\r\n" );
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document.write( "Then since p=6d, p=6(4) = 24\r\n" );
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document.write( "So there are 3 dimes and 24 pennies.\r\n" );
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document.write( "Edwin
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