document.write( "Question 366355: An integer is seven more than another integer. Twice the larger integer is one less than the square of the smaller integer. Find the two integers. \n" ); document.write( "
Algebra.Com's Answer #261038 by mananth(16946)\"\" \"About 
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let one integer be x
\n" ); document.write( "the other is x+7
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\n" ); document.write( "twice the larger = 2(x+7)
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\n" ); document.write( "1 less than square of the smaller
\n" ); document.write( "x^2-1
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\n" ); document.write( "x^2-1=2(x+7)
\n" ); document.write( "x^2-1=2x+14
\n" ); document.write( "x^2-2x-1-14=0
\n" ); document.write( "x^2-2x-15=0
\n" ); document.write( "x^2-5x+3x-15=0
\n" ); document.write( "x(x-5)+3(x-5)=0
\n" ); document.write( "(x-5)(x+3)=0
\n" ); document.write( "x=5 OR x= -3
\n" ); document.write( "the integers are 5, 12
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\n" ); document.write( "m.ananth@hotmail.ca
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