document.write( "Question 366326: A teen club has weekly dances. You can become a member of the club for $30 a year and pay only $4 to attend each dance. Otherwise each dance costs $6. How many dances do you have to attend so that becoming a member will cost less than paying the nonmember rate? \n" ); document.write( "

Algebra.Com's Answer #261009 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"d\"$ = number of dances you need to attend to break even
\n" ); document.write( "Let $\"C\"$ = cost for member and non-member
\n" ); document.write( "For member:
\n" ); document.write( " $\"C+=+30+%2B+4d\"$
\n" ); document.write( "For non-member:
\n" ); document.write( " $\"C+=+6d\"$
\n" ); document.write( "When are the costs the same?
\n" ); document.write( " $\"30+%2B+4d+=+6d\"$
\n" ); document.write( " $\"2d+=+30\"$
\n" ); document.write( " $\"d+=+15\"$
\n" ); document.write( "When you attend 16 dances, the cost as a member
\n" ); document.write( "is less than a non-member
\n" ); document.write( "check:
\n" ); document.write( "For 15 dances:
\n" ); document.write( "For member:
\n" ); document.write( " $\"C+=+30+%2B+4%2A15\"$
\n" ); document.write( " $\"C+=+90\"$
\n" ); document.write( "For non-member:
\n" ); document.write( " $\"C+=+6%2A15\"$
\n" ); document.write( " $\"C+=+90\"$
\n" ); document.write( "And for 16 dances:
\n" ); document.write( "For member:
\n" ); document.write( " $\"C+=+30+%2B+4%2A16\"$
\n" ); document.write( " $\"C+=+94\"$
\n" ); document.write( "For non-member:
\n" ); document.write( " $\"C+=+6%2A16\"$
\n" ); document.write( " $\"C+=+96\"$
\n" ); document.write( "OK\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );