document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366314>Question 366314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 more than its width. The perimeter of the rectangle is 58 centimeters. What are the rectangle's dimensions?\r<BR>\n" );
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document.write( "Directions: Write a system of equations to represent the situation. Then solve the system by substitution.\r<BR>\n" );
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document.write( "Please help me!!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260992 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be x cm<BR>\n" );
document.write( "length will be x+3 cm<BR>\n" );
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document.write( "Perimeter = 2*(L+W)<BR>\n" );
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document.write( "2*(x+x+3)=58<BR>\n" );
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document.write( "2*(2x+3)=58<BR>\n" );
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document.write( "(2x+3)=29<BR>\n" );
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document.write( "2x+3-3=29-3<BR>\n" );
document.write( "2x=26<BR>\n" );
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document.write( "x=13 ----- the width<BR>\n" );
document.write( "length = x+3=13+3=16 cm.\r<BR>\n" );
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document.write( "..<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
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