document.write( "Question 40689: I am wondering if I factored this correctly?\r
\n" ); document.write( "\n" ); document.write( "The roof is 7 m from peak to eave and the attic space is 3 m high at the peak, how long does each of the pieces of insulation need to be?\r
\n" ); document.write( "\n" ); document.write( "I come up with x = 33
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Algebra.Com's Answer #26098 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Hmmm...let's see if I've got this right:\r
\n" ); document.write( "\n" ); document.write( "The roof is 7 meters from peak to eave. This forms one side (the hypotenuse) of a right triangle, right?
\n" ); document.write( "The attic space is 3 meters high at the peak. This forms the perpendicular height of the same of the same right triangle.
\n" ); document.write( "So you need to find the distance, x, of the base of this triangle, and this goes halfway across the attic.\r
\n" ); document.write( "\n" ); document.write( "Calling upon Pythagorus, you have:
\n" ); document.write( "\"7%5E2+=+x%5E2+%2B+3%5E2\"
\n" ); document.write( "\"49+=+x%5E2+%2B+9\" Subtracting 9 from both sides:
\n" ); document.write( "\"x%5E2+=+40\" Taking the square root of both sides, you'll get:
\n" ); document.write( "\"x+=+6.3\" meters. \r
\n" ); document.write( "\n" ); document.write( "Now since this is halfway across the attic, you'll need to double this to get 12.65 meters (Approximtely)
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