document.write( "Question 366114: Evening Everybody
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document.write( " Stuck on this question. (trying to get back in to the swing of things so i can enrol on a course)\r
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document.write( "i) Given that F.r is the work done by a force F in moving a body through displacement r. Find the work done by the force F= 3i+7k. if it causes a body to move from the point A with coordinates (1,1,2) to the point B with coordinates (7,3,5)\r
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document.write( "ii) Obtain unit vectors in each of the directions of f=i+j+3k and s=2i-j+k. Hence show that 48/sqrt66 joules is the work done when a force of magnitude 6 newtons in the direction f moves its point of application a distance 2 metres parallel to s .\r
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document.write( "Really appreciate help on this. \n" );
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Algebra.Com's Answer #260939 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Find \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "which is equivalent to \n" ); document.write( " \n" ); document.write( " |