document.write( "Question 366057: how many liters of a 10% alcohol solution must be mixed with 90 liters of a 50% solution to get a 20% solution \n" ); document.write( "

Algebra.Com's Answer #260900 by Fombitz(32388) $\"\"$ $\"About$

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Let $\"A\"$ be the amount of 10% alcohol solution.
\n" ); document.write( " $\"10A%2B50%2890%29=20%28A%2B90%29\"$
\n" ); document.write( " $\"10A%2B4500=20A%2B1800\"$
\n" ); document.write( " $\"A%2B450=2A%2B180\"$
\n" ); document.write( " $\"highlight%28A=270%29\"$ liters.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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