document.write( "Question 366017: Please help me solve this equation:
\n" ); document.write( "Find equations of the tangents to the curve $\"+x+=+3t%5E2%2B1+\"$ , $\"+y=2t%5E3%2B1+\"$ that pass through the point (4,3). \n" ); document.write( "

Algebra.Com's Answer #260875 by Jk22(389) $\"\"$ $\"About$

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from (x,y) = (4,3)
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\n" ); document.write( "we find t = 1
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\n" ); document.write( "the tangent slope is dy/dx = 6t²/6t = 1 for t = 1
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\n" ); document.write( "then tangent equation is : y = x - 1 at (4,3), or y = t - 1, x = t
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