document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366030>Question 366030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I solve?\r<BR>\n" );
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document.write( "3*5^(2t-1)=75\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260860 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3*5^(2t-1) = 75  | dividing by 3<BR>\n" );
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document.write( "5^(2t-1) = 25 = 5^2 | equating exponents, or log()/log(5)<BR>\n" );
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document.write( "2t - 1 = 2, | adding 1<BR>\n" );
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document.write( "2t = 3 |dividing by 2<BR>\n" );
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document.write( "t = 3/2\r<BR>\n" );
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