document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366005>Question 366005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose S varies directly as the 2/3 power of T, and that S=16 when T=8. Find S when T= 27 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260830 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S varies directly as the 2/3 power of T.\r<BR>\n" );
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document.write( "This means that S = k*T^(2/3)\r<BR>\n" );
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document.write( "When S = 16, T = 8\r<BR>\n" );
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document.write( "This means that 16 = k*(8^(2/3))\r<BR>\n" );
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document.write( "Simplify this to get 16 = k * 4\r<BR>\n" );
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document.write( "This makes k = 4\r<BR>\n" );
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document.write( "Now that you know the value of k, use the same formula to find S when T = 27.\r<BR>\n" );
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document.write( "You get S = k*T(2/3)) which becomes:\r<BR>\n" );
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document.write( "S = 4*(27^(2/3)) which becomes:\r<BR>\n" );
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document.write( "S = 4*9 which becomes\r<BR>\n" );
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document.write( "S = 36\r<BR>\n" );
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document.write( " </SPAN>\n" );
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