document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366005>Question 366005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose S varies directly as the 2/3 power of T, and that S=16 when T=8. Find S when T= 27 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260826 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose S varies directly as the 2/3 power of T, and that S=16 when T=8. Find S when T= 27\r<BR>\n" );
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document.write( "Let k = the constant\r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "    S = k * T^2/3<BR>\n" );
document.write( "   16 = k * 8^(2/3)<BR>\n" );
document.write( "   16 = k * (8^1/3)^2<BR>\n" );
document.write( "   16 = k * (2)^2<BR>\n" );
document.write( "  16/4= k = 4\r<BR>\n" );
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document.write( "When T =27,\r<BR>\n" );
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document.write( "     S = k * T^2/3<BR>\n" );
document.write( "     S = k * 27^2/3<BR>\n" );
document.write( "       = 4 * 3^2<BR>\n" );
document.write( "       = 36\r<BR>\n" );
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document.write( "S = 36 when T = 27<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );