document.write( "Question 365989: In a triangular cross section of a roof, the second angle is twice as large as the first. The third angle is 20 greater than the first angle. How large are the angles?
\n" ); document.write( "first angle=x
\n" ); document.write( "second angle = 2x
\n" ); document.write( "third angle = x+20 \n" ); document.write( "

Algebra.Com's Answer #260821 by Theo(13342) $\"\"$ $\"About$

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sum of the angles of a triangle is 180.
\n" ); document.write( "first angle is x.
\n" ); document.write( "second angle is 2*x
\n" ); document.write( "third angle is x + 20.\r
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\n" ); document.write( "\n" ); document.write( "x + 2*x + x + 20 = 180\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get 4*x + 20 = 180\r
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\n" ); document.write( "\n" ); document.write( "subtract 20 from both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "4*x = 160\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 4 to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 160/4 = 40\r
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\n" ); document.write( "\n" ); document.write( "the first angle is 40 degrees.
\n" ); document.write( "the second angle is 80 degrees.
\n" ); document.write( "the third angle is 60 degrees.\r
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\n" ); document.write( "\n" ); document.write( "40 + 80 + 60 = 180 degrees.\r
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