document.write( "Question 365988: In a triangular cross section of a roof, the seconf angle is twice as large as the first. The third angle is 20 greater than the first angle. how large are the angles?
\n" ); document.write( "first angle = x
\n" ); document.write( "second angle = 2x
\n" ); document.write( "third angle = x+20
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Algebra.Com's Answer #260811 by amoresroy(361)\"\" \"About 
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In a triangular cross section of a roof, the seconf angle is twice as large as the first. The third angle is 20 greater than the first angle. how large are the angles?
\n" ); document.write( "first angle = x
\n" ); document.write( "second angle = 2x
\n" ); document.write( "third angle = x+20\r
\n" ); document.write( "\n" ); document.write( "Since the sum of 3 angles in a triangle is 180, the equation is
\n" ); document.write( "x+2x+(x+20) = 180
\n" ); document.write( " 4x = 180 -20
\n" ); document.write( " x = 40\r
\n" ); document.write( "\n" ); document.write( " 2x = 2(40) = 80
\n" ); document.write( "
\n" ); document.write( " x+20 = 40+20 = 60\r
\n" ); document.write( "\n" ); document.write( "The angles are 40, 80, & 60.
\n" ); document.write( "The sum is 180.
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