document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=365938>Question 365938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Randy invested his inheritance in an account that paid 6.3% interest,<BR>\n" );
document.write( "compounded continuously. After 6 years, he found that he now had $48,541.33<BR>\n" );
document.write( "What was the original amount of his inheritance? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260790 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A= p(1+r/n)^nt<BR>\n" );
document.write( "A= Future Value<BR>\n" );
document.write( "p = invested amount<BR>\n" );
document.write( "r=rate of interest<BR>\n" );
document.write( "n = compounding period<BR>\n" );
document.write( "t = time in years<BR>\n" );
document.write( "...<BR>\n" );
document.write( "48541.33 = p*(1+(0.063/365)^(365*6)<BR>\n" );
document.write( "p= (48541.33)/(1+(0.063/365)^(365*6)<BR>\n" );
document.write( "p= $33263.08<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );