document.write( "Question 365882: The perimiter of the quadrilateral is 35 centimeters. Find the length of each side.
\n" ); document.write( "side 1 = x+2
\n" ); document.write( "side 2 = x+7
\n" ); document.write( "side 3 = x squared - 2x
\n" ); document.write( "side 4 = 3x-2 \n" ); document.write( "

Algebra.Com's Answer #260766 by robertb(5830) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28x%2B2%29%2B%28x%2B7%29+%2B+%28x%5E2-2x%29+%2B+%283x-2%29+=+35\"$ ,
\n" ); document.write( " $\"x%5E2%2B3x%2B7+=+35\"$ ,
\n" ); document.write( " $\"x%5E2+%2B3x-28+=+0\"$ ,
\n" ); document.write( " $\"%28x%2B7%29%28x-4%29+=+0\"$ ,
\n" ); document.write( "or x = -7 or x = 4. Drop the first value. Therefore
\n" ); document.write( "side 1 = 6 cm,
\n" ); document.write( "side 2 = 11 cm,
\n" ); document.write( "side 3 = 8 cm, and
\n" ); document.write( "side 4 = 10 cm. \n" ); document.write( "

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