document.write( "Question 365807: a salesperson is late for a meeting after traveling from one town to another at a speed of 32 mph. If she had gone 4 mph faster, she could have made the trip in one-half hour less time. How far apart are the towns? \n" ); document.write( "
Algebra.Com's Answer #260730 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let the distance between towns be x miles
\n" ); document.write( "..
\n" ); document.write( "time = distance /speed\r
\n" ); document.write( "\n" ); document.write( "time = x/32 hours
\n" ); document.write( "..
\n" ); document.write( "4mph faster
\n" ); document.write( "x+4
\n" ); document.write( "time = x/36 hours
\n" ); document.write( "..
\n" ); document.write( "x/32-x/36 =1/2
\n" ); document.write( "(36x-32x)/32*36= 1/2
\n" ); document.write( "4x=1/2 * 36*32
\n" ); document.write( "4x=576
\n" ); document.write( "/4
\n" ); document.write( "x=144 miles the distance
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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