document.write( "Question 365807: a salesperson is late for a meeting after traveling from one town to another at a speed of 32 mph. If she had gone 4 mph faster, she could have made the trip in one-half hour less time. How far apart are the towns? \n" ); document.write( "
Algebra.Com's Answer #260730 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the distance between towns be x miles \n" ); document.write( ".. \n" ); document.write( "time = distance /speed\r \n" ); document.write( "\n" ); document.write( "time = x/32 hours \n" ); document.write( ".. \n" ); document.write( "4mph faster \n" ); document.write( "x+4 \n" ); document.write( "time = x/36 hours \n" ); document.write( ".. \n" ); document.write( "x/32-x/36 =1/2 \n" ); document.write( "(36x-32x)/32*36= 1/2 \n" ); document.write( "4x=1/2 * 36*32 \n" ); document.write( "4x=576 \n" ); document.write( "/4 \n" ); document.write( "x=144 miles the distance \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |