document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=365798>Question 365798</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Casey has 15 pounds of cashews that sell for $5.25 per pound. If peanuts sell for $2.50 per pound, how many pounds of peanuts should he add to cashews to obtain a mixturethat will sell for $3.75 per pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260725 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260725\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15 pounds of cashews  $5.25 per pound. <BR>\n" );
document.write( "peanuts  $2.50 per pound, x pounds<BR>\n" );
document.write( "mixture  $3.75 per pound? x+15 pounds<BR>\n" );
document.write( "...<BR>\n" );
document.write( "15*5.25+2.50*x=3.75(x+15)<BR>\n" );
document.write( "78.75+2.50x=3.75x+56.25<BR>\n" );
document.write( "3.75x-2.50x=78.75-56.25<BR>\n" );
document.write( "1.25x=12.50<BR>\n" );
document.write( "x= 12.50/1.25<BR>\n" );
document.write( "x= 10 pounds of peanuts<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
document.write( " </SPAN>\n" );
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