document.write( "Question 365679: a cylindrical aluminum can has a volume of 500 cubic centimeters. if each square centimeter of aluminum cost .05 cents, express the cost of material for the can as a function of the radius r of the can. \n" ); document.write( "
Algebra.Com's Answer #260722 by ankor@dixie-net.com(22740)\"\" \"About 
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a cylindrical aluminum can has a volume of 500 cubic centimeters.
\n" ); document.write( " if each square centimeter of aluminum cost .05 cents, express the cost
\n" ); document.write( " of material for the can as a function of the radius r of the can.
\n" ); document.write( ":
\n" ); document.write( "Use the volume equation to get h in terms of r
\n" ); document.write( "\"pi%2Ar%5E2%2Ah\" = 500
\n" ); document.write( "Divide both sides by \"pi%2Ar%5E2\"
\n" ); document.write( "h = \"500%2F%28%28pi%2Ar%5E2%29%29\"
\n" ); document.write( ":
\n" ); document.write( "The surface area of a cylinder including the two ends
\n" ); document.write( "S.A. = \"2%2Api%2Ar%2Ah\" + \"2%2Api%2Ar%5E2\"
\n" ); document.write( "Get the surface area in terms of r, replace h with \"500%2F%28%28pi%2Ar%5E2%29%29\"
\n" ); document.write( "S.A. = \"2%2Api%2Ar%2A%28500%2F%28pi%2Ar%5E2%29%29\" + \"2%2Api%2Ar%5E2\"
\n" ); document.write( "we can cancel pi*r
\n" ); document.write( "S.A. = \"2%2A%28500%2Fr%29\" + \"2%2Api%2Ar%5E2\"
\n" ); document.write( "Factor out 2
\n" ); document.write( "S.A. = 2(\"%28500%2Fr%29+%2B+%28pi%2Ar%5E2%29\")
\n" ); document.write( "To find the cost, multiply by .05
\n" ); document.write( "C(r) = .05*2(\"%28500%2Fr%29+%2B+%28pi%2Ar%5E2%29\")
\n" ); document.write( ":
\n" ); document.write( "C(r) = .1(\"%28500%2Fr%29+%2B+%28pi%2Ar%5E2%29\"); cost of material in terms of r
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