document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40666>Question 40666</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321233832/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> steve traveled 600 miles at a certain speed. had he gone 20mph faster, the trip would have taken 1 hour less.  Find the speed of his vehicle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26071 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 600/X=(600/X+20)-1 OR 600/X=(600-X-20)/(X+20) OR 600X-X~2-20X=600X-12,000 OR <BR>\n" );
document.write( "-X~2-20X=-12,000 OR X~2+20X-12,000 OR (X-100)(X+120)=0 OR X=100 MPH\r<BR>\n" );
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document.write( "THEN X+20=120 MPH \r<BR>\n" );
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document.write( "PROOX 600/100=6 HOURS & 600/120=5 HOURS 6-5=1 HOUR LESS @ 120 MPH.  </SPAN>\n" );
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