document.write( "Question 365782: factor completely
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Algebra.Com's Answer #260708 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"36r%5E2-49\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%286r%29%5E2-49\" Rewrite \"36r%5E2\" as \"%286r%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%286r%29%5E2-%287%29%5E2\" Rewrite \"49\" as \"%287%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "Notice how we have a difference of squares \"A%5E2-B%5E2\" where in this case \"A=6r\" and \"B=7\".\r
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\n" ); document.write( "\n" ); document.write( "So let's use the difference of squares formula \"A%5E2-B%5E2=%28A%2BB%29%28A-B%29\" to factor the expression:\r
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\n" ); document.write( "\n" ); document.write( "\"A%5E2-B%5E2=%28A%2BB%29%28A-B%29\" Start with the difference of squares formula.\r
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\n" ); document.write( "\n" ); document.write( "\"%286r%29%5E2-%287%29%5E2=%286r%2B7%29%286r-7%29\" Plug in \"A=6r\" and \"B=7\".\r
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\n" ); document.write( "\n" ); document.write( "So this shows us that \"36r%5E2-49\" factors to \"%286r%2B7%29%286r-7%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words \"36r%5E2-49=%286r%2B7%29%286r-7%29\".\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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