document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5138>Question 5138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the factors of 2x*x-27x+36=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2607 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+-+27x++%2B+36+=+0 ALIGN=MIDDLE  ALT=\"2x%5E2+-+27x++%2B+36+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Are you familiar with FOIL method of expanding products of binomials?  If not, then resubmit this question, and I'll try another method.\r<BR>\n" );
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document.write( "If you understand the FOIL menthod, then the answer has to be in the form:<BR>\n" );
document.write( "(2x - ____)(x - ____), where the product of the numbers on the blank lines is 36.  \r<BR>\n" );
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document.write( "Also, the numbers have to be such that when you multiply the OUTER times OUTER and INNER times INNER, you end up with a sum of 27x. \r<BR>\n" );
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document.write( "All the combinations of 36 are listed below:<BR>\n" );
document.write( "1*36<BR>\n" );
document.write( "2*18<BR>\n" );
document.write( "3*12<BR>\n" );
document.write( "4*9<BR>\n" );
document.write( "6*6\r<BR>\n" );
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document.write( "Because the middle term is odd, you can't have an even times even number.  This eliminates teh 2*18 and the 6 * 6 combinations.  After some trial and error, the one that works is the 3*12 combination:<BR>\n" );
document.write( "(2x - 3)(x - 12), since the outer times outer is -24x, the inner times inner is -3x, and that adds up to -27x.\r<BR>\n" );
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document.write( "So, you have it factored into<BR>\n" );
document.write( "(2x-3)(x-12) = 0\r<BR>\n" );
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document.write( "Set each factor equal to zero, and solve for x.<BR>\n" );
document.write( "(2x-3)(x-12) = 0<BR>\n" );
document.write( " 2x - 3 = 0  <BR>\n" );
document.write( "2x = 3<BR>\n" );
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document.write( "x-12= 0<BR>\n" );
document.write( "x= 12\r<BR>\n" );
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document.write( "Final answer:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=+3%2F2 ALIGN=MIDDLE  ALT=\"x=+3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=+12 ALIGN=MIDDLE  ALT=\"x=+12\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2 at SCC \r<BR>\n" );
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document.write( " </SPAN>\n" );
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