document.write( "Question 365563: Karen can jog to work in 2/3 of an hour. When she rides her bike, it takes her 1/4 of an hour. If she rides 11 miles per hour faster than she jogs, how far away is her work? \n" ); document.write( "
Algebra.Com's Answer #260683 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Karen can jog to work in 2/3 of an hour. When she rides her bike, it takes her 1/4 of an hour. If she rides 11 miles per hour faster than she jogs, how far away is her work? \n" ); document.write( ": \n" ); document.write( "First find her speed by writing a distance equation, dist = time * speed \n" ); document.write( "let s = K's jogging speed \n" ); document.write( "then \n" ); document.write( "(s+11) = biking time \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "4(2s) = 3(s+11) \n" ); document.write( "8s = 3s + 33 \n" ); document.write( "8s - 3s = 33 \n" ); document.write( "5s = 33 \n" ); document.write( "s = \n" ); document.write( "s = 6.6 mph is the jogging speed \n" ); document.write( "then \n" ); document.write( "6.6 + 11 = 17.6 mph is her biking speed \n" ); document.write( ": \n" ); document.write( "Find the distance with the jogging speed \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Confirm the distance using the biking speed \n" ); document.write( " |