document.write( "Question 365563: Karen can jog to work in 2/3 of an hour. When she rides her bike, it takes her 1/4 of an hour. If she rides 11 miles per hour faster than she jogs, how far away is her work? \n" ); document.write( "
Algebra.Com's Answer #260683 by ankor@dixie-net.com(22740)\"\" \"About 
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Karen can jog to work in 2/3 of an hour. When she rides her bike, it takes her 1/4 of an hour. If she rides 11 miles per hour faster than she jogs, how far away is her work?
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\n" ); document.write( "First find her speed by writing a distance equation, dist = time * speed
\n" ); document.write( "let s = K's jogging speed
\n" ); document.write( "then
\n" ); document.write( "(s+11) = biking time
\n" ); document.write( ":
\n" ); document.write( "\"2%2F3\"s = \"1%2F4\"(s+11)
\n" ); document.write( "Cross multiply
\n" ); document.write( "4(2s) = 3(s+11)
\n" ); document.write( "8s = 3s + 33
\n" ); document.write( "8s - 3s = 33
\n" ); document.write( "5s = 33
\n" ); document.write( "s = \"33%2F5\"
\n" ); document.write( "s = 6.6 mph is the jogging speed
\n" ); document.write( "then
\n" ); document.write( "6.6 + 11 = 17.6 mph is her biking speed
\n" ); document.write( ":
\n" ); document.write( "Find the distance with the jogging speed
\n" ); document.write( "\"2%2F3\"*6.6 = 4.4 mi is the distance to word
\n" ); document.write( ":
\n" ); document.write( "Confirm the distance using the biking speed
\n" ); document.write( "\"1%2F4\"*17.6= 4.4
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