document.write( "Question 365680: \"+ln%28t%2F%28t-4%29%29=1+\"\r
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Algebra.Com's Answer #260661 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"+ln%28t%2F%28t-4%29%29=1+\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"+ln%28t%2F%28t-4%29%29=ln%28e%29+\" Rewrite 1 as \"ln%28e%29\". Recall that \"ln%28e%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "Since the logs have the same base (e), this means that the arguments (the stuff inside the logs) are equal.\r
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\n" ); document.write( "\n" ); document.write( "Formally, if \"ln%28x%29=ln%28y%29\", then \"x=y\"\r
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\n" ); document.write( "\n" ); document.write( "\"+t%2F%28t-4%29=e+\" Use the property given above to set the arguments equal to each other.\r
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\n" ); document.write( "\n" ); document.write( "\"+t=e%28t-4%29+\" Multiply both sides by \"t-4\".\r
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\n" ); document.write( "\n" ); document.write( "\"+t=et-4e+\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"+t-et=-4e+\" Subtract et from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"+t%281-e%29=-4e+\" Factor out the GCF 't'.\r
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\n" ); document.write( "\n" ); document.write( "\"+t=-4e%2F%281-e%29+\" Divide both sides by \"1-e\" to isolate 't'.\r
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\n" ); document.write( "\n" ); document.write( "Optional Step: You can rewrite \"1-e\" as \"-e%2B1=-%28e-1%29\" and notice how the negatives cancel in the numerator and denominator. So \"t=4e%2F%28e-1%29\" also\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"+t=-4e%2F%281-e%29+\"\r
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\n" ); document.write( "\n" ); document.write( "You can also write the solution as \"t=4e%2F%28e-1%29\" (the two are equivalent).\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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