document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=361532>Question 361532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the meausure of an angle is 20 more than 3 times the meausure of its supplement. What is the smaller angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260648 by </B><A HREF=/tutors/aboutme.mpl?userid=apachemexican1><B>apachemexican1(64)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=apachemexican1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the meausure of an angle is 20 more than 3 times the meausure of its supplement. What is the smaller angle?\r<BR>\n" );
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document.write( "the supplementary angles add up to 180 degrees<BR>\n" );
document.write( "so the equation will be set up like so<BR>\n" );
document.write( "3x+20+x=180 <BR>\n" );
document.write( "combine like terms<BR>\n" );
document.write( "4x+20=180<BR>\n" );
document.write( "subtract 20 from both sides of the equation<BR>\n" );
document.write( "4x+20-20=180-20<BR>\n" );
document.write( "equals<BR>\n" );
document.write( "4x=160<BR>\n" );
document.write( "you then divide 4 from both sides of the equation<BR>\n" );
document.write( "4x/4=160/4<BR>\n" );
document.write( "solve for x<BR>\n" );
document.write( "x=40\r<BR>\n" );
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document.write( "so the smaller angle is 40 degrees<BR>\n" );
document.write( "if u were lookin for the measure of the bigger angle as well you would just subtract the smaller angle by 180 and then u would have the bigger angle as well </SPAN>\n" );
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