document.write( "Question 365593: a rectangle whose perimeter is two hundred feet has a width that is twelve feet shorther than its height. what are the dimensions of the rectangle?\r
\n" ); document.write( "\n" ); document.write( "a rectangle's length is seven times its width the perimeter of the rectangle is two hundred and twenty four feet. what are the dimensions of the rectange? \n" ); document.write( "

Algebra.Com's Answer #260616 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "*Note;  Key to these is assigning a variable.
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document.write( "Let x represent the height, then the width would be (x -12)
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document.write( "x + x + (x -12) + (x -12) = 200ft
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document.write( "x = 56ft, is the height and the width 44ft  (56-12)
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document.write( "checking our answer
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document.write( "2*56ft + 2* 44ft = 200ft
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document.write( "112ft + 88ft = 200 ft\r
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document.write( "Second Set up is:
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document.write( "Let x represent the width, then the length would be 7x
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document.write( "Let You take it from there. \n" );
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