document.write( "Question 365524: what are three consecutive positive numbers such that the product of the first and third, minus the second,is one more than five times the third \n" ); document.write( "
Algebra.Com's Answer #260601 by ankor@dixie-net.com(22740)\"\" \"About 
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Three consecutive numbers, x, (x+1), (x+2)
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\n" ); document.write( "Write an equation for just what it says:
\n" ); document.write( "\"the product of the first and third, minus the second,is one more than five times the third\"
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\n" ); document.write( "x(x+2) - (x+1) = 5(x+2) + 1
\n" ); document.write( "x^2 + 2x - x - 1 = 5x + 10 + 1
\n" ); document.write( "x^2 + x - 1 = 5x + 11
\n" ); document.write( "Combine to form a quadratic equation
\n" ); document.write( "x^2 + x - 5x - 1 - 11 = 0
\n" ); document.write( "x^2 - 4x + 12 = 0
\n" ); document.write( "Factors to:
\n" ); document.write( "(x-6)(x-2) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 6
\n" ); document.write( "x = 2
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\n" ); document.write( "The numbers:
\n" ); document.write( "6, 7, 8
\n" ); document.write( "and
\n" ); document.write( "2, 3, 4
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\n" ); document.write( "Check both solutions in the original equation
\n" ); document.write( "1st set: 6(8) - 7 = 5(8) + 1; a good solution
\n" ); document.write( "and
\n" ); document.write( "2nd set: 2(4) - 3 = 5(4) + 1; doesn't work
\n" ); document.write( " therefore
\n" ); document.write( "x = 6 is the only solution \n" ); document.write( "
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