document.write( "Question 365565: Solve for r:\r
\n" ); document.write( "\n" ); document.write( "v=1/3(pi)h^2(3r-h)\r
\n" ); document.write( "\n" ); document.write( "I solved it to get (h+v)/(3pi h^2)=r
\n" ); document.write( "The solution book says it should be:
\n" ); document.write( "(3v+pi h^3)/(3pi h^2)\r
\n" ); document.write( "\n" ); document.write( "What did I do wrong? Or is the book wrong?
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Algebra.Com's Answer #260599 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Solve for r:
\n" ); document.write( "v=1/3(pi)h^2(3r-h)
\n" ); document.write( "3r-h = 3v/(pi*h^2)
\n" ); document.write( "3r = h + 3v/(pi*h^2)
\n" ); document.write( "3r = (3v + pi*h^3)/(pi*h^2)
\n" ); document.write( "r = (3v + pi*h^3)/(3pi*h^2)
\n" ); document.write( "---------
\n" ); document.write( "This is the formula for the volume of liquid h units deep in a spherical tank of radius r.
\n" ); document.write( "Solving for h is more difficult.
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