document.write( "Question 365549: Abraham invested $42,000 in two accounts. The first paid 8% interest per year and the second paid 3% per year. He earned a total of $2960 in one year. How much did he invest at 8%? \n" ); document.write( "

Algebra.Com's Answer #260595 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


\n" );
document.write( "Hi, 
\n" );
document.write( "Let x represent amount invested at 8%
\n" );
document.write( "then ($42,000 - x) would be amount invested at 3%
\n" );
document.write( "Question states
\n" );
document.write( ".08x + .03($42,000-x) = $2960
\n" );
document.write( ".05x = $2960 - .03*$42,000
\n" );
document.write( ".05x = $2960 - $1260
\n" );
document.write( ".05x = 1700
\n" );
document.write( "x = $34,000, amount invested at 8%
\n" );
document.write( "checking our answer
\n" );
document.write( "$2720 + $240 = $2660 \n" );
document.write( "

\n" );