document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=365546>Question 365546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the rational zeros and synthetic division to factor f(x)=x^3+x^2-5x-2.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260585 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260585\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the rational zeros and synthetic division to factor f(x)=x^3+x^2-5x-2. <BR>\n" );
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document.write( "Graphing I found a rational zero at x = 2<BR>\n" );
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document.write( "Using synthetic division you can find the following:<BR>\n" );
document.write( "2)....1....1....-5....-2<BR>\n" );
document.write( ".......1....3.....1..|..0\r<BR>\n" );
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document.write( "Quotient: x^2+3x+1<BR>\n" );
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document.write( "Use the Quadratic formula to find the other zeroes:<BR>\n" );
document.write( "x = [-3 +- sqrt(9-4*1*1)]/2<BR>\n" );
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document.write( "x = [-3 +- sqrt(5)]/2<BR>\n" );
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document.write( "x = (-3+sqrt(5))/2 or x = (-3-sqrt(5))/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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