document.write( "Question 365461: Graph the line that is perpendicular to the graph of 7x+10y=4.5 and intersects that graph at its x-intercept. \n" ); document.write( "

Algebra.Com's Answer #260547 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "***General point-slope from of an equation is 
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document.write( "y = mx + b where m is the slope and b is the value of y where the line crosses the y-axis
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document.write( "7x+10y=4.5
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document.write( "y = (-7/10)x + 4.5/10 
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document.write( "0 = (-7/10)x + 4.5/10      x-intercept is when y = 0
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document.write( " x-intercept = (9/14)\r
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document.write( "Slope of the new line 1s 10/7
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document.write( "( perpendicular lines have slopes that are negativie reciprocals of one another)
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document.write( "10/7 is the negative reciprocal of -7/10
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document.write( "y = (10/7)x + b
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document.write( "Using ordered pair ((9/14),0) to solve for b
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document.write( ".918 = b
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document.write( "y = (10/7)x + .918
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