document.write( "Question 365462: graph the line that passes through the point (6,-3), perpindicular to aline whose slope is 1/1/2. \n" ); document.write( "

Algebra.Com's Answer #260543 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "***General point-slope from of an equation is 
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document.write( "y = mx + b where m is the slope and b is the value of y where the line crosses the y-axis
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document.write( "Slope of this line 1s -2/3 
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document.write( "( perpendicular lines have slopes that are negativie reciprocals of one another)
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document.write( "-2/3 is the negative reciprocal of 3/2
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document.write( "y = (-2/3)x + b
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document.write( "Using ordered pair (6,-3) to solve for b
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document.write( "-3 = (-2/3)*6 + b
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document.write( "-3 + 4 = b
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document.write( "1 = b
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document.write( "y = (-2/3)x + 1
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