document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=365455>Question 365455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measures of two complementary angles are in the ratio 1:5.Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260531 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the measure of smaller angle<BR>\n" );
document.write( "   5x = the measure of bigger angle \r<BR>\n" );
document.write( "\n" );
document.write( "Complementary angles add up to 90\r<BR>\n" );
document.write( "\n" );
document.write( "x+5x = 90<BR>\n" );
document.write( "  6x = 90<BR>\n" );
document.write( "   x = 15<BR>\n" );
document.write( "  5x = 5(15) = 75\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );