document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=365348>Question 365348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are lengthened by 8 cm, the area becomes 144 cm^2. Find the length of a side of the original square.\r<BR>\n" );
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document.write( "What is the length of a side of the original square is ? cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260526 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET ORIGINAL LENGTH BE X<BR>\n" );
document.write( "INCREASED BY 8<BR>\n" );
document.write( "NEW LENGTH = X+8<BR>\n" );
document.write( "Area = L^2<BR>\n" );
document.write( "(x+8)^2= 144<BR>\n" );
document.write( "x^+16x+64=144<BR>\n" );
document.write( "x^2+16x-80=0<BR>\n" );
document.write( "x^2+20x-4x-80=0<BR>\n" );
document.write( "x(x+20)-4(x+20)=0<BR>\n" );
document.write( "(x+20)(x-4)=0<BR>\n" );
document.write( "x = 4 the original length of square<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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