document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=365377>Question 365377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The chemist wants 100 gallons when complete. He is mixing a 24% solution with a 50% solution to get a 36% solution. How many gallons of each will he use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260498 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  when complete. He is mixing a 24% solution with a 50% solution to get a 36% solution. How many gallons of each will he use?<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x gallons ------------ 24%<BR>\n" );
document.write( "(100-x)gallons ------- 50%<BR>\n" );
document.write( "Mixture =  100 gallons--36%<BR>\n" );
document.write( "...<BR>\n" );
document.write( "0.24x+(100-x)*0.5 = 0.36*100<BR>\n" );
document.write( "0.24x+50-0.5x=36<BR>\n" );
document.write( "0.24x-0.50x=36-50<BR>\n" );
document.write( "-0.26x=-14<BR>\n" );
document.write( "/0.26<BR>\n" );
document.write( "x=  53.8 gallons of 24%<BR>\n" );
document.write( "46.2  gallons of 50%<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );