document.write( "Question 365410: Five years ago sister was four times older than Fido. Now she is only three times as old. How is old is Fido? \n" ); document.write( "
Algebra.Com's Answer #260480 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Fido - x years now \n" ); document.write( "Sister --- 3x years \n" ); document.write( ".. \n" ); document.write( "5 years ago \n" ); document.write( "Fido'age = x-5 years \n" ); document.write( "Sister's age = 3x-5 years \n" ); document.write( "... \n" ); document.write( "3x-5 =4(x-5) \n" ); document.write( "3x-5=4x-20 \n" ); document.write( "4x-3x=20-5 \n" ); document.write( "x=15 Fido's age now \n" ); document.write( "sister's age = 3x =45 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |