document.write( "Question 365410: Five years ago sister was four times older than Fido. Now she is only three times as old. How is old is Fido? \n" ); document.write( "
Algebra.Com's Answer #260480 by mananth(16946)\"\" \"About 
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Fido - x years now
\n" ); document.write( "Sister --- 3x years
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\n" ); document.write( "5 years ago
\n" ); document.write( "Fido'age = x-5 years
\n" ); document.write( "Sister's age = 3x-5 years
\n" ); document.write( "...
\n" ); document.write( "3x-5 =4(x-5)
\n" ); document.write( "3x-5=4x-20
\n" ); document.write( "4x-3x=20-5
\n" ); document.write( "x=15 Fido's age now
\n" ); document.write( "sister's age = 3x =45
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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