document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=365296>Question 365296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve and graph on a number line:<BR>\n" );
document.write( "-2(a-3)+ 3(a+2)< 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260419 by </B><A HREF=/tutors/aboutme.mpl?userid=jokaehler><B>jokaehler(26)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jokaehler><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jokaehler><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) In order to solve this problem, you need to make sure that your problem is > 0, not > 4. How we do this is we subtract 4 from both sides.\r<BR>\n" );
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document.write( "Now we should have: 2(a-3)+3(a+2)-4>0<BR>\n" );
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document.write( "2) Make sure to use the distributive property. Let's start with 2(a-3). 2*a, and you will have 2a. 2*-3, and you will have -6.<BR>\n" );
document.write( "Now we should have: 2a-6+3(a+2)-4>0<br><BR>\n" );
document.write( "3)Repeat this same process (distributive property) with 3(a+2).<BR>\n" );
document.write( "Now we should have: 2a-6+3a+6>0<br><BR>\n" );
document.write( "4)Combine like terms<BR>\n" );
document.write( "Now we should have:5a>0<br><BR>\n" );
document.write( "5)Divide both sides by 5.<BR>\n" );
document.write( "Now we should have a>0\r<BR>\n" );
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document.write( "Plot this on a number line. Open circle pointing to the positive side and continuing </SPAN>\n" );
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