document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=365082>Question 365082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am struggling with a distance formula problem that has radicands in the points. I am ok with doing the distance formula d=square root of (x2-x1)sq +(y2-y1)sq.<BR>\n" );
document.write( "the points I am trying to find the distance between are:<BR>\n" );
document.write( "(4 square root of 2, 3 square root of 5) and (-2 square root of 2, 5 square root of 5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260372 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4 square root of 2, 3 square root of 5) and (-2 square root of 2, 5 square root of 5)<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "(4*sqrt(2),3*sqrt(5)) and (-2*sqrt(2),5*sqrt(5))<BR>\n" );
document.write( "diffy = 2sqrt(5)<BR>\n" );
document.write( "diffx = 6sqrt(2)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+sqrt%28diffy%5E2+%2B+diffx%5E2%29+=+sqrt%2820+%2B+72%29 ALIGN=MIDDLE  ALT=\"d+=+sqrt%28diffy%5E2+%2B+diffx%5E2%29+=+sqrt%2820+%2B+72%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "d = sqrt(92)<BR>\n" );
document.write( "d =~ 9.59<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );