document.write( "Question 364834: A runner decides to run out in the country. He begins to run at an average rate of 9 miles per hour. He runs a certain distance and then turns around and returns along the same route at an average rate of 6 miles per hour. If the round trip took two and a half hours, how far did the runner travel before turning around? \n" ); document.write( "
Algebra.Com's Answer #260352 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A runner decides to run out in the country. \n" ); document.write( " He begins to run at an average rate of 9 miles per hour. \n" ); document.write( " He runs a certain distance and then turns around and returns along the same \n" ); document.write( " route at an average rate of 6 miles per hour. \n" ); document.write( " If the round trip took two and a half hours, how far did the runner travel \n" ); document.write( " before turning around? \n" ); document.write( ": \n" ); document.write( "Let d = one-way distance (point of turning around) \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( ": \n" ); document.write( "outbound time + return time = 2.5 hrs \n" ); document.write( " \n" ); document.write( "Multiply by 18 to clear the denominators, results: \n" ); document.write( "2d + 3d = 18(2.5) \n" ); document.write( "5d = 45 \n" ); document.write( "d = \n" ); document.write( "d = 9 miles out in the country before turning around. \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that's true \n" ); document.write( " \n" ); document.write( "1 + 1.5 = 2.5 \n" ); document.write( " |