document.write( "Question 364913: Dave and Cindy played 53 games of backgammon last month. Dave's ratio of wins to losses was 37/16.
\n" ); document.write( "If Dave and Cindy play 10 more games, write a proportion to determine how many of these 10 games dave could expect to win.\r
\n" ); document.write( "\n" ); document.write( "Determine how many more games Dave and Cindy must play before Cindy will have won a total of 28 games.
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Algebra.Com's Answer #260309 by ankor@dixie-net.com(22740)\"\" \"About 
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Dave and Cindy played 53 games of backgammon last month.
\n" ); document.write( " Dave's ratio of wins to losses was 37/16.
\n" ); document.write( "If Dave and Cindy play 10 more games, write a proportion to determine how many
\n" ); document.write( " of these 10 games dave could expect to win.
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\n" ); document.write( "If the proportion remains the same for these 10 games:
\n" ); document.write( "\"37%2F53\" * 10 ~ 7 games
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\n" ); document.write( "Determine how many more games Dave and Cindy must play before Cindy will have
\n" ); document.write( " won a total of 28 games.
\n" ); document.write( "Let x = no. of additional games for this to happen
\n" ); document.write( "\"16%2F53\" = \"28%2F%28%28x%2B53%29%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "16(x+53) = 28 * 53
\n" ); document.write( "16x + 848 = 1484
\n" ); document.write( "16x = 1484 - 848
\n" ); document.write( "x = \"636%2F16\"
\n" ); document.write( "x ~ 40 more games
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\n" ); document.write( "Check this:
\n" ); document.write( "original per cent: 16/53 ~ .3
\n" ); document.write( "40 more games percent: 28/93 ~ .3
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