document.write( "Question 364913: Dave and Cindy played 53 games of backgammon last month. Dave's ratio of wins to losses was 37/16.
\n" );
document.write( "If Dave and Cindy play 10 more games, write a proportion to determine how many of these 10 games dave could expect to win.\r
\n" );
document.write( "\n" );
document.write( "Determine how many more games Dave and Cindy must play before Cindy will have won a total of 28 games. \n" );
document.write( "
Algebra.Com's Answer #260309 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Dave and Cindy played 53 games of backgammon last month. \n" ); document.write( " Dave's ratio of wins to losses was 37/16. \n" ); document.write( "If Dave and Cindy play 10 more games, write a proportion to determine how many \n" ); document.write( " of these 10 games dave could expect to win. \n" ); document.write( ": \n" ); document.write( "If the proportion remains the same for these 10 games: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Determine how many more games Dave and Cindy must play before Cindy will have \n" ); document.write( " won a total of 28 games. \n" ); document.write( "Let x = no. of additional games for this to happen \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "16(x+53) = 28 * 53 \n" ); document.write( "16x + 848 = 1484 \n" ); document.write( "16x = 1484 - 848 \n" ); document.write( "x = \n" ); document.write( "x ~ 40 more games \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this: \n" ); document.write( "original per cent: 16/53 ~ .3 \n" ); document.write( "40 more games percent: 28/93 ~ .3 \n" ); document.write( " \n" ); document.write( " |