document.write( "Question 365047: Evening All.
\n" ); document.write( " Struggling on this vectors problem.\r
\n" ); document.write( "\n" ); document.write( "i)If a and b are perpendicular, then by writing a= ¦a¦ and b= ¦b¦ simplify the expression (a-2b).(3a+5b)\r
\n" ); document.write( "\n" ); document.write( "ii)Show that the vectors a=i+2j and b=4i-2j are perpendicular\r
\n" ); document.write( "\n" ); document.write( "iii) Find the angle theta in degrees between the vectors p=i-j-k and q=2i+j+2k\r
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Algebra.Com's Answer #260304 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Struggling on this vectors problem.
\n" ); document.write( "i)If a and b are perpendicular, then by writing a= ¦a¦ and b= ¦b¦ simplify the expression (a-2b).(3a+5b)
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document.write( "Sorry I don't understand \"writing a= ¦a¦ and b= ¦b¦\".  If you\r\n" );
document.write( "can explain what that means I can help you.  Here are the others:\r\n" );
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\n" ); document.write( "ii)Show that the vectors a=i+2j and b=4i-2j are perpendicular
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document.write( "Just show that their dot product (scalar product) is 0:\r\n" );
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document.write( "(i+2j)·(4i-2j) = (1)(4)+(2)(-2) = 4-4 = 0\r\n" );
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\n" ); document.write( "iii) Find the angle theta in degrees between the vectors p=i-j-k and q=2i+j+2k
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document.write( "Use the formula \r\n" );
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document.write( "           u·v \r\n" );
document.write( "cos(@) = ------ =\r\n" );
document.write( "         |u||v|\r\n" );
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document.write( " =\r\n" );
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document.write( "\"%282-1-2%29%2F%28%28sqrt%281%2B1%2B1%29%29sqrt%284%2B1%2B4%29%29\" =\r\n" );
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document.write( "\"%28-1%29%2F%28%28sqrt%283%29%29sqrt%289%29%29\" = \"-1%2F%28%28sqrt%283%29%29%283%29%29\" = \"-1%2F%283sqrt%283%29%29\" = \"%28-1%2F%283sqrt%283%29%29%29%28sqrt%283%29%2Fsqrt%283%29%29\" = \"-sqrt%283%29%2F%28%283%29%283%29%29\" = \"-sqrt%283%29%2F9\"\r\n" );
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document.write( "So @ = 101.1° approximately\r\n" );
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document.write( "Edwin
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