document.write( "Question 18511: Find the area of an equilateral triangle whose vertices lie on a circle with radius 2cm. \n" ); document.write( "
Algebra.Com's Answer #26027 by tran3209(100)![]() ![]() ![]() You can put this solution on YOUR website! Let ABC be the equilateral triangle whose verticle lie on the circle with a radius of 2cm and \"O\" as the center.\r \n" ); document.write( "\n" ); document.write( "AH the perpendicular from A to BC is the altitude\r \n" ); document.write( "\n" ); document.write( "In an equilateral triangle the altitude is also the median.\r \n" ); document.write( "\n" ); document.write( "So O is also the centroid of the triangle \r \n" ); document.write( "\n" ); document.write( "So ---->OH/AO = ½ \n" ); document.write( " \n" ); document.write( "OH= OA/2 = 2/2 = 1cm\r \n" ); document.write( "\n" ); document.write( "AH=2+1=3cm\r \n" ); document.write( "\n" ); document.write( "In the triange OCH\r \n" ); document.write( "\n" ); document.write( "OC=2cm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "OH=1cm\r \n" ); document.write( "\n" ); document.write( "apply the pythagorean theorem\r \n" ); document.write( "\n" ); document.write( "OC^2= OH^2 + HC^2 \n" ); document.write( "or \n" ); document.write( "HC^2 =OC^2 - OH^2\r \n" ); document.write( "\n" ); document.write( "=2^2-1^2\r \n" ); document.write( "\n" ); document.write( "=4-1=3 \n" ); document.write( "HC = √3\r \n" ); document.write( "\n" ); document.write( "The side of the triangle BC =2HC = 2√3\r \n" ); document.write( "\n" ); document.write( "The area of the triangle:\r \n" ); document.write( "\n" ); document.write( "AH X BC \n" ); document.write( "------- \n" ); document.write( " 2 \n" ); document.write( "= 2 X 2√3 \n" ); document.write( " -------- \n" ); document.write( " 2\r \n" ); document.write( "\n" ); document.write( "= 4√3 \n" ); document.write( " ----- \n" ); document.write( " 2 \n" ); document.write( "Area of the triangle is 2√3 cm^2 \n" ); document.write( " \n" ); document.write( " |