document.write( "Question 18511: Find the area of an equilateral triangle whose vertices lie on a circle with radius 2cm. \n" ); document.write( "
Algebra.Com's Answer #26027 by tran3209(100)\"\" \"About 
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Let ABC be the equilateral triangle whose verticle lie on the circle with a radius of 2cm and \"O\" as the center.\r
\n" ); document.write( "\n" ); document.write( "AH the perpendicular from A to BC is the altitude\r
\n" ); document.write( "\n" ); document.write( "In an equilateral triangle the altitude is also the median.\r
\n" ); document.write( "\n" ); document.write( "So O is also the centroid of the triangle \r
\n" ); document.write( "\n" ); document.write( "So ---->OH/AO = ½
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\n" ); document.write( "OH= OA/2 = 2/2 = 1cm\r
\n" ); document.write( "\n" ); document.write( "AH=2+1=3cm\r
\n" ); document.write( "\n" ); document.write( "In the triange OCH\r
\n" ); document.write( "\n" ); document.write( "OC=2cm\r
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\n" ); document.write( "\n" ); document.write( "OH=1cm\r
\n" ); document.write( "\n" ); document.write( "apply the pythagorean theorem\r
\n" ); document.write( "\n" ); document.write( "OC^2= OH^2 + HC^2
\n" ); document.write( "or
\n" ); document.write( "HC^2 =OC^2 - OH^2\r
\n" ); document.write( "\n" ); document.write( "=2^2-1^2\r
\n" ); document.write( "\n" ); document.write( "=4-1=3
\n" ); document.write( "HC = √3\r
\n" ); document.write( "\n" ); document.write( "The side of the triangle BC =2HC = 2√3\r
\n" ); document.write( "\n" ); document.write( "The area of the triangle:\r
\n" ); document.write( "\n" ); document.write( "AH X BC
\n" ); document.write( "-------
\n" ); document.write( " 2
\n" ); document.write( "= 2 X 2√3
\n" ); document.write( " --------
\n" ); document.write( " 2\r
\n" ); document.write( "\n" ); document.write( "= 4√3
\n" ); document.write( " -----
\n" ); document.write( " 2
\n" ); document.write( "Area of the triangle is 2√3 cm^2
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