document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=365021>Question 365021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 15. Find the amount of money in an account after 12 years if a principal of $1800 was invested at 4.4% interest compounded quarterly. Round to the nearest cent.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260261 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the amount of money in an account after 12 years if a principal of $1800 was invested at 4.4% interest compounded quarterly. Round to the nearest cent.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "A= p(1+r/n) ^nt<BR>\n" );
document.write( "p=1800<BR>\n" );
document.write( "r=4.4% = 0.044<BR>\n" );
document.write( "t= period 12 years<BR>\n" );
document.write( "n= quarterly = 4<BR>\n" );
document.write( "A= 1800(1+0.044/4)^(12*4)<BR>\n" );
document.write( "Amount = $ 3043.18 <BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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