document.write( "Question 365004: pure acid is to be added to a 10% acid solution to obtain 90l of 75% solution? what amounts should each be used? \n" ); document.write( "

Algebra.Com's Answer #260235 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "Let x represent amount of pure acid(this will be an 100% solution) (90L-x the 10% solution
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document.write( "Write as we Read***
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document.write( ".10(90L-x) + 1.00x = .75*90L
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document.write( "solving for x
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document.write( ".90x = .65*90L
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document.write( "x = 65L, the amount of pure acid. 
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document.write( "(90-65L)=25L   the amount of the 10% solution
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document.write( "checking our answer
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document.write( "2.5 + 65 = 67.5 \n" );
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