document.write( "Question 40620:
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document.write( "x + 3/x lessthan or eqaul to -2
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document.write( "(I don't know why this dosen't post right. x + 3 over x is lessthen or eqaul to -2)
Algebra.Com's Answer #26019 by junior403(76)![]() ![]() ![]() You can put this solution on YOUR website! Solve the rational inequality and state the solution set using interval notation. \n" ); document.write( " \n" ); document.write( "Ok, first we need to eliminate the fraction \n" ); document.write( "This will create an equation that we can work with more easily. \n" ); document.write( " \n" ); document.write( "Now we can simplify by canceling out the x's on the left side and multiplying on the right. \n" ); document.write( " \n" ); document.write( "Now we can subtract the x from both sides of the equation... \n" ); document.write( "x + 3 - x = 3 and -2x -x = -3x \n" ); document.write( "so... \n" ); document.write( " \n" ); document.write( "Now, this may get a little tricky... \n" ); document.write( "We need to isolate the variable x. In order to do that we need to divide both sides by -3. \n" ); document.write( "However, the rule for inequalities is that when we divide by a NEGATIVE number, we ALWAYS have to chanbge the inequality sign. so... \n" ); document.write( " \n" ); document.write( "And remember to change the sign. \n" ); document.write( "So... \n" ); document.write( " \n" ); document.write( "So this tells us that our variable x will always be less than or equal to -1. \n" ); document.write( "The bracket ] tells us that -1 is included. \n" ); document.write( "So we show this in interval notation... \n" ); document.write( "(-~,-1] or (negative infinity, -1] \n" ); document.write( "I hope this helps. \n" ); document.write( "Good Luck! \n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |